——

The sum of the squares of the first ten natural numbers is,

12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

——

**My Solution:**

```
.text
.globl main
main:
/*-enter stack frame-*/
pushl %ebp
movl %esp, %ebp
/*find square of sums*/
movl $0, %eax
movl $1, %ebx
addNumbers:
cmpl $100, %ebx
jg doneAdding
addl %ebx, %eax
addl $1, %ebx
jmp addNumbers
doneAdding:
movl %eax, %ebx
imul %ebx, %eax
/*find sum of squares*/
movl $0, %ebx
movl $1, %ecx
squareNumbers:
cmpl $100, %ecx
jg doneSquaring
movl %ecx, %edx
movl %ecx, %edi
imul %edx, %edi
addl %edi, %ebx
addl $1, %ecx
jmp squareNumbers
doneSquaring:
subl %ebx, %eax
pushl %eax
pushl $string2
call printf
/*-leave stack frame-*/
movl %ebp, %esp
popl %ebp
movl $0, %eax
ret
.data
string2: .string "result=%dn"
```