Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:
1, 2, 3, 5, 8, 13, 21, 34, 55, 89, …
By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms.
My solution using Scheme:
(define (remainder x y) (- x (* y (truncate (/ x y))))) (define (fib a b limit) (if (< a limit) (if (= 0 (remainder a 2)) (+ a (fib b (+ a b) limit)) (fib b (+ a b) limit)) 0 ) ) (display (fib 1 2 4000000))