In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:

1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).

It is possible to make £2 in the following way:

1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p

How many different ways can £2 be made using any number of coins?

## My Solution

```
#include <stdio.h>
int countWays(int total,int set[],int size){
if (total<0)
return 0;
if (total==0)
return 1;
if (size==1)
return 1;
else
return countWays(total,set,size-1)+countWays(total-set[size-1],set,size);
}
int main(){
int total=200;
int set[]={1,2,5,10,20,50,100,200};
int result;
int size = 8;
result = countWays(total,set,size);
printf("%d\n",result);
return 0;
}
```

Cristian GallardoHow can I print each coins combination?