Problem 6 has the following description:

The sum of the squares of the first ten natural numbers is,

12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

The solution is straight forward:

```
#include <stdio.h>
int main(){
int i,j,y,sum1,sum2;
sum=0;
for (i=1;i<101;i++)
sum+=i*i;
y=0;
for (j=1;j<101;j++){
y=y+j;
}
sum2=y*y;
printf("Answer: %dn",sum2-sum);
return 0;
}
```